Question

The helicopter in the drawing is moving horizontally to the right at a constant velocity. The weight of the helicopter is W=50900 N. The lift force L generated by the rotating blade makes an angle of 21.0° with respect to the vertical.
(a) What is the magnitude of the lift force?
(b) Determine the magnitude of the air resistance R that opposes the motion.

Answer 1

Answer:

a.$L=54521.3 N$

b.$R=19518.6 N$

Explanation:

We are given that

Weight of the helicopter=50900 N

The lift force L generated by the rotating blade makes an angle of 21..0 degree with respect to the vertical.

a.We have to find the magnitude of the lift force.

According to question

$Lcos 21^{\circ}=50900$

$L=\frac{50900}{cos21^{\circ}}=54521.3 N$

b.We  have to determine the magnitude of air resistance R that opposes the motion.

R=$F_x$

$Lsin21^{\circ}=R$

$R=54521.3\times 0.358=19518.6 N$