Answer:
[tex]4\frac{17}{20}[/tex]
Step-by-step explanation:
We have been given that Mr. Neville Iceguy mixed up 12 3/5 gallons of chili for a party. 7 3/4 gallons of chili was mild.
To find the amount of extra spicy chili, we will subtract amount of mild chili from total chili as:
[tex]12\frac{3}{5}-7\frac{3}{4}[/tex]
Convert mixed fraction into improper fraction:
[tex]12\frac{3}{5}\Rightarrow \frac{12\times 5+3}{5}=\frac{60+3}{5}=\frac{63}{5}[/tex]
[tex]7\frac{3}{4}\Rightarrow \frac{7\times 4+3}{4}=\frac{28+3}{4}=\frac{31}{4}[/tex]
[tex]12\frac{3}{5}-7\frac{3}{4}\Rightarrow\frac{63}{5}-\frac{31}{4}[/tex]
Make a common denominator:
[tex]\frac{63*4}{5*4}-\frac{31*5}{4*5}[/tex]
[tex]\frac{252}{20}-\frac{155}{20}[/tex]
Combine numerators:
[tex]\frac{252-155}{20}[/tex]
[tex]\frac{97}{20}[/tex]
[tex]4\frac{17}{20}[/tex]
Therefore, Mr. Iceguy made [tex]4\frac{17}{20}[/tex] gallons of extra spicy chili.
