Answers:
a) 10 m
b) time=1.6 s, frquency=0.625 Hz
c) 6.25 m/s
Explanation:
a) If there is a crest at each dock and another three crests between the two docks, and the wavelength [tex]\lambda[/tex] is the distance between to crests; this means we have [tex]4\lambda[/tex] in [tex]40 m[/tex]:
[tex]40 m=4\lambda[/tex]
Clearing [tex]\lambda[/tex]:
[tex]\lambda=\frac{40 m}{4}[/tex]
[tex]\lambda=10 m[/tex]
b) This part can be solved by a Rule of Three:
If 10 waves ---- 16 s
1 wave ----- [tex]T[/tex]
Then:
[tex]T=\frac{(1 wave)(16 s)}{10 waves}[/tex]
[tex]T=1.6 s[/tex] This is the period of the wave
On the other hand, the frequency [tex]f[/tex] of the wave has an inverse relation with its period [tex]T[/tex]:
[tex]f=\frac{1}{T}[/tex]
[tex]f=\frac{1}{1.6 s}[/tex]
[tex]f=0.625 Hz[/tex] This is the frequency of the wave
c) The speed [tex]v[/tex] of a wave is given by the following equation:
[tex]v=\frac{\lambda}{T}[/tex]
[tex]v=\frac{10 m}{1.6 s}[/tex]
Finally:
[tex]v=6.25 m/s[/tex]