Answer:
[tex]f(x)=162^\frac{x}{4}[/tex]
[tex]f(x)=[3\sqrt[4]{2}]^{x}[/tex]
[tex]f(x)=[3(2^{\frac{1}{4}})]^{x}[/tex]
Step-by-step explanation:
we have
[tex]f(x)=\sqrt[4]{162^{x}}[/tex]
Remember that
[tex]\sqrt[n]{a^{m}}=a^{m/n}[/tex]
[tex](a^{m})^{n}=a^{m*n}[/tex]
so
1) [tex]\sqrt[4]{162^{x}}=162^\frac{x}{4}[/tex]
2) The number 162 decompose in prime factors is
[tex]162=(2)(3^4)[/tex]
substitute
[tex]f(x)=\sqrt[4]{[(2)(3^4)]^{x}}={[(2)(3^4)]^{x/4}={{[(2)(3^4)]^{(1/4)}}^x=[3\sqrt[4]{2}]^{x}[/tex]
3) [tex]f(x)=[3\sqrt[4]{2}]^{x}=[3(2^{\frac{1}{4}})]^{x}[/tex]
therefore
[tex]f(x)=162^\frac{x}{4}[/tex]
[tex]f(x)=[3\sqrt[4]{2}]^{x}[/tex]
[tex]f(x)=[3(2^{\frac{1}{4}})]^{x}[/tex]
