Answer:
No solution for the problem
Step-by-step explanation:
- Carl traveled the 1900 km from his home in Eastern Ontario to
Winnipeg
- He traveled by bus to Toronto at an average speed of 60 km/h
- Then flew to Winnipeg at an average speed of 100 km/h
- His total travelling time was 7 hours
- We need to find the distance he traveled by bus and by airplane
∵ The total distance he traveled is 1900 km
- If he traveled d km by airplane, then the distance traveled by bus
is 1900 - d
- The total time is 7 hrs
∴ The time of the bus + the time of the airplane = 7
∵ The time of the bus = the distance by bus ÷ the speed of the bus
∵ The speed of the bus = 60 km/h
∵ The distance by bus = 1900 - d
∴ The time of the bus = [tex]\frac{1900-d}{60}[/tex]
∵ The speed of the airplane = 100 km/h
∵ The distance by airplane = d
∴ The time of the airplane = [tex]\frac{d}{100}[/tex]
∵ The total time = 7 hours
∴ [tex]\frac{d}{100}+\frac{1900-d}{60}=7[/tex]
- To cancel the denominator multiply all the terms by 600
∴ 6d + 10(1900 - d) = 4200
∴ 6d + 19000 - 10d = 4200
- Add like terms in the left hand side
∴ -4d + 19000 = 4200
- subtract 19000 from both sides
∴ -4d = -14800
- Divide both sides by -4
∴ d = 3700
∵ d represents the distance traveled by airplane
∴ The distance traveled by airplane is 3700 Km and that is impossible
because the total distance is 1900 km which is less than this distance,
and the distance traveled by bus will be - 1800 km
