Question

An airplane starts at rest and accelerates at 6.8 m/s2 at an angle of 39° south of west. After 9 s, how far in the westerly direction has the airplane traveled?

Answer 1

Answer:36.8

Explanation:

Answer 2

We have that the westerly direction has the airplane traveled is

W=57.25m

From the question we are told that

• An airplane starts at rest and accelerates at 6.8 m/s2
• an angle of 39° south of west
• After 9 s,  

Generally the Newtons  equation for the Distance   is mathematically given as

$s=ut+1/2at^2\\\\s=ut+1/2(6.8)(9)^2\\\\s=275.4m$

Therefore

The airplane's Western travel

$W=scos2\theta\\\\W=275.4cos2(39)\\\\W=57.25m$

The airplane's southern travel

$W=ssin2\theta\\\\W=275.4sin2(39)\\\\W==269.38m$

For more information on this visit

https://brainly.com/question/12319416?referrer=searchResults