Question

Which is equivalent to 80 Superscript one-fourth x?

(StartFraction 80 Over 4 EndFraction) Superscript x
RootIndex 4 StartRoot 80 EndRoot Superscript x
RootIndex x StartRoot 80 EndRoot Superscript 4
(StartFraction 80 Over x EndFraction) Superscript 4

Answer 1

Answer:

The equivalent statement is $(\sqrt[4]{80})^{x}$ ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Any root can be a fraction power

- Ex: $\sqrt{a}=a^{\frac{1}{2}}$

   $\sqrt[3]{a}=a^{\frac{1}{3}}$

   $\sqrt[4]{a}=a^{\frac{1}{4}}$

   $\sqrt[n]{a}=a^{\frac{1}{n}}$

* The expression is $(80)^{\frac{1}{4}x}$

∵ $(80)^{\frac{1}{4}x}$ can be written as $(80^{\frac{1}{4}})^{x}$

∵ $(80)^{\frac{1}{4}}=\sqrt[4]{80}$

∴ $(80^{\frac{1}{4}})^{x}$ = $(\sqrt[4]{80})^{x}$

* The equivalent statement is $(\sqrt[4]{80})^{x}$

Answer 2

Answer:

B

Step-by-step explanation:

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