Question

a spinner is divided into five equal sections labeled 1 to 5. What is the probability that the spinner will land on 3?

Answer 1

Since there are 5 options, that's gonna be the denominator. And since there is only one number 3, 1 is our numerator. So the finish fraction is 1/5.

There is 1/5 probability that the spinner will land on 3.

Answer 2

Answer: $\dfrac{1}{5}$

Step-by-step explanation:

Given : A spinner is divided into five equal sections labeled 1 to 5.

Thus , the total number of sections on the spinner =5

Number of favorable outcomes =1

Then , the probability that the spinner will land on 3 is given by :-

$\dfrac{\text{Favorable outcome}}{\text{Total outcomes}}\\\\=\dfrac{1}{5}$

Hence, the probability that the spinner will land on 3 is $\dfrac{1}{5}$