[tex]\sf\ For\ ax^2+bx+c=0\ the\ quadratic\ formula\ is\ x=\frac{-b\± \sqrt{b^{2}-4ac} }{2a}.\\You\ can\ use\ this\ formula\ to\ solve\ the\ problem.\\\\\\\\I'm\ presuming\ that\ your\ equation\ is\ x^2+4x+3=0\\\\\\\\a=1\\\\\ b=4\\\\ c=3\\\\\\\\Plug\ it\ in\ the\ quadratic\ formula.\\\\\\\\x=\frac{-b\± \sqrt{b^{2}-4ac} }{2a}\\\\x=\frac{-(4)\± \sqrt{(4)^{2}-4(1)(3)} }{2(1)}\\\\x=\frac{-4\± \sqrt{16-4(3)} }{2}\\\\x=\frac{-4\± \sqrt{16-12} }{2}\\\\x=\frac{-4\± \sqrt{4} }{2}\\\\x=\frac{-4\±2}{2}[/tex]
[tex]\sf\ So\ now\ we\ have\ x=\frac{-4+2}{2}\ and\ x=\frac{-4-2}{2}.\\\\\\\\x=\frac{-4+2}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac{-4-2}{2}\\\\x=\frac{-2}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac{-6}{2}\\\\x=-1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-3\\\\\\\\{\boxed{\sf\ x=-1\ \ or\ \ x=-3}[/tex]
