Answer:
a)[tex]20\ \rm m/s^2[/tex]
b) 80 m
Explanation:
Given:
Using Equation of motion we have
a)Let a be the acceleration of the object
[tex]v=u+at\\60=20+2a\\a=20\ \rm m/s^2[/tex]
b) Let d be the distance covered by the object given by
Using equation of motion we have
[tex]2ad=v^2-u^2\\2\times20\times d=60^2-20^2\\d=80\ \rm m[/tex]