Question

A daredevil jumps a canyon 10.5 m wide. To do so, he drives a car up a 17° incline. (The daredevil lands on the other side of the canyon at the same elevation as takeoff.) (a) What minimum speed must he achieve to clear the canyon? m/s (b) If the daredevil jumps at this minimum speed, what will his speed be when he reaches the other side? m/s

Answer 1

Answer:

minimum speed is 13.56 m/s

and

there is no friction so same speed on landing on the other side

Explanation:

given data

wide = 10.5 m

angle = 17 degree

to find out

What minimum speed and If the daredevil jumps at this minimum speed, what will his speed be when he reaches the other side

solution

we will apply here distance formula that is

distance = $\frac{v^2sin(2a)}{g}$

put here value distance and a angle and g 9.8 m/s² and v is speed

10.5 = $\frac{v^2sin(34)}{9.8}$

v = 13.56

minimum speed is 13.56 m/s

and

there is no friction so same speed on landing on the other side

and under ideal conditions in parabolic motion the velocity remains the same