Question

If the temperature changes by 100 K, by how much does it change in °C?

Answer 1

Answer:

100K − 273.15 = -173.1°C

Answer 2

Answer:

∆T is same in both K as well as in ℃ (Answer)

Explanation:

Temperature change is represented by ∆T

∆T= $T_{final} - T_{initial}$

∆T is same in both K as well as in ℃ (Answer)

Suppose if the temperature increases from 0℃ to 10℃

∆T = 10℃ - 0℃ = 10℃

In Kelvin

$T_{final}$ = 10℃ + 273 = 283K

$T_{initial}$ = 0℃ + 273 = 273 K

∆T = 283 K - 273 K = 10 K .

Thus, it is proved that ∆T is same in both K as well as in ℃ (Answer)