Can somebody help me please!!!
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Answer:
Part A: 0
Part B: 0 or 1
Step-by-step explanation:
Part A: anything to the 0 power is 1 (x^0= x^y-y) if you solve 7^2 you get 49. 49^0= 1
Part B: Because it is already being raised to the power of 0, if x=0 it will remain equal to one (as explained above). Anything raised to the 1 power is itself, so 7^0= 1 and 1^1 =1
Hope this helped!