Respuesta :
Answer:
[tex]\forall x\in D[/tex] if x is odd then x> 0 is true statement.
[tex]\forall x\in D[/tex] if x is odd then x> 0 is true statement.
[tex]\forall x\in D[/tex] if x is even then x≤0 is false statement.
[tex]\forall x\in D[/tex] If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.
[tex]\forall x\in D[/tex] if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.
Step-by-step explanation:
Consider the provided information.
D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}
Part (A) [tex]\forall x\in D[/tex] if x is odd then x> 0
Here only even numbers are less than 0 that means the statement is true.
[tex]\forall x\in D[/tex] if x is odd then x> 0 is true statement.
Part (B) [tex]\forall x\in D[/tex] if x is less than 0 then x is even.
Here only even numbers are less than 0 that means the statement is true.
[tex]\forall x\in D[/tex] if x is odd then x> 0 is true statement.
Part (C) [tex]\forall x\in D[/tex] if x is even then x≤0
Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.
[tex]\forall x\in D[/tex] if x is even then x≤0 is false statement.
Part (D) [tex]\forall x\in D[/tex] If the ones digit of x is 2, then the tens digit is 3 or 4.
There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.
[tex]\forall x\in D[/tex] If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.
Part (E) [tex]\forall x\in D[/tex] if the ones digit of x is 6, then the tens digit is 1 or 2.
Numbers having ones digit 6 are: 16, 26 and 36
Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.
[tex]\forall x\in D[/tex] if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.