Question

6t -20-32u6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=
4
1
​ u, equals, start fraction, 1, divided by, 4, end fraction.

Answer 1

The question is:

Evaluate 6t−20−32u when t=6 and u=1/4

Answer:

8

Step-by-step explanation:

The given expression is:

$6t-20-32u$

We need to evaluate the expression for the given values of t and u. Substituting t=6 and u=1/4 in the above expression we get:

$6(6)-20-32(\frac{1}{4} )\\\\ =36-20-8\\\\ =8$

Thus, the give expression is equal to 8 for t=6 and u=1/4

Answer 2

Answer:

8

Step-by-step explanation:

Let's substitute t = 6 and u = 1/4 into the expression.

6t - 20 - 32u

= 6(6) - 20 - 32(1/4)

= 36 - 20 - 8

= 8

Hope you understood! <3