Use the elimination method to solve the system of equations.
3x+4y=8
X-Y=12
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STEP 1: Multiply second equation by -3.
After multiplying we have the following system:
3x+4y−3x+3y=8=−36
STEP 2: add the two equations together to eliminate x from the system.
7y=−28
STEP 3: find y
y=−4
STEP 4: substitute the value for y into the original equation to solve for x.
3x+4(−4)=8
x=8
Answer: D. (8, -4)
Step-by-step explanation:
3x + 4y = 8 --------------(1)
x - y = 12--------------(2)
eqn(2) × 3
3x - 3y = 36-----------(4)
eqn(4) - eqn(1)
-7y = 28
Divide bothside by -7
y = -4
Again, multiply eqn(2) by 4
4x - 4y = 48 ---------------(5)
eqn(5) + eqn(1)
7x = 56
Divide bothside by 7
x = 8
Therefore x=8 and y=-4