Answer: [tex]1/10^8[/tex]
Step-by-step explanation:
Here the total numbers are 10 ( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
Since, the probability of choosing one number = [tex]\frac{1}{10}[/tex]
Therefore, the probability of choosing 8 numbers =
[tex]\frac{1}{10}\times\frac{1}{10}\times \frac{1}{10}\times \frac{1}{10}\times \frac{1}{10}\times \frac{1}{10}\times \frac{1}{10}\times \frac{1}{10}\times [/tex] ( because there is no replacement)
= [tex]\frac{1}{10^8}[/tex]
