Question

An alligator swims to the left with a constant velocity of 5 \,\dfrac{\text{m}}{\text s}5
s
m
​ 5, space, start fraction, m, divided by, s, end fraction. When the alligator sees a bird straight ahead, the alligator speeds up with a constant acceleration of 3 \,\dfrac{\text {m}}{\text s^2}3
s
2

m
​ 3, space, start fraction, m, divided by, s, start superscript, 2, end superscript, end fraction leftward until it reaches a final velocity of 35 \,\dfrac{\text {m}}{\text s}35
s
m
​ 35, space, start fraction, m, divided by, s, end fraction leftward.
How many seconds does it take the alligator to speed up from 5 \,\dfrac{\text {m}}{\text s}5
s
m
​ 5, space, start fraction, m, divided by, s, end fraction to 35 \,\dfrac{\text {m}}{\text s}35
s
m
​ 35, space, start fraction, m, divided by, s, end fraction?
Answer using a coordinate system where rightward is positive.
must be a decimal

Answer 1

Answer:

10s

Explanation:

girl idk, its what Khan Academy said

Answer 2

Answer:

time is 10s

Explanation:

given data

Initial Velocity  u  = 5 m/s

Acceleration  a = 3 m/s²

Final Velocity v  = 35 m/s

to find out

time period

solution

as motion of alligator is in motion with constant acceleration

so we use here equation of motion  

v = u + at   .................1

put here value and we get

35 = 5 + 3t

3t = 35 - 5

t = $\frac{30}{3}$  

t = 10

so time is 10s