Answer:
5.89 x 10²⁴Joules
Explanation:
Given parameters:
Volume of earth's ocean = 137 x 10⁷ km³
Density of sea water = 1.03g/cm³
Specific heat capacity of water = 4.184J/g°C
Unknown:
Quantity of heat to warm earth's oceans by 1.0°C?
Solution:
Heat is thermal energy that moves from one body to another as a result of changes in temperature of such a body.
The expression for the quantity of heat is given as:
q = mcΔT
m is the mass, c is the specific heat capacity and ΔT is the temperature change
From the given parameters, mass m is unknown
To calculate the mass:
mass = density x volume
Convert the volume to cubic centimeter
1km³ = 1 x 10¹⁵cm³
137 x 10⁷km³ = 137 x 10²²cm³
mass of sea water = 1.03g/cm³ x 137 x 10²²cm³ = 141.11 x 10²²g
Therefore from:
q = mcΔT
q = 141.11 x 10²²g x 4.184J/g°C x 1°C = 5.9 x10²⁴joules