Question

how do i find the limit of number 2?

Answer 1

The numerator has degree 1, and the denominator has degree 2. For large $x$, the denominator will dominate, so the limit would be 0.

Put another way, we have

$\dfrac{2x+7}{x^2-x}=\dfrac{\frac2x+\frac7{x^2}}{1-\frac1x}$

and each fraction with $x$ will aproach 0. The numerator itself approaches 0 while the denominator approaches 1, so the overall limit is 0.