Answer:
12 seconds
Step-by-step explanation:
The given function is
[tex]h=192t-16t^2[/tex]
where h represents the height of the flare in feet above the sea t sec after it is launched.
We need to find the time taken by flare to return to the sea. At sec level the height of flare is 0.
Substitute h=0 in the given function.
[tex]0=192t-16t^2[/tex]
[tex]0=16t(12-t)[/tex]
Using zero product property we get
[tex]16t=0\Rightarrow t=0[/tex]
[tex](12-t)=0\Rightarrow t=12[/tex]
It means at t=0 and t=12 the flare is at sea level.
The time taken by flare to return to the sea is
[tex]12-0=12[/tex]
Therefore, the time taken by flare to return to the sea is 12 seconds.