Question

(a) If 1 mol of a gas in a container occupies a volume of 12 L at a pressure of 1 atm, what is the temperature of the gas in kelvins? K You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) (b) The container is fitted with a piston so that the volume can change. When the gas is heated at constant pressure, it expands to a volume of 25 L. What is the temperature of the gas in kelvins? K You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 3) (c) The volume is fixed at 25 L, and the gas is heated at constant volume until its temperature is 346 K. What is the pressure of the gas?

Answer 1

Answer:

• (a) T = 146.34 K
• (b) T = 304.88 K
• (c) P = 1.13 atm

Explanation:

To solve this problem we use the Ideal Gas equation:

PV=nRT

Where P is pressure (in atm), V is volume (in L), n is the number of moles, T is temperature (in K), and R is a constant (0.082 atm·L·mol⁻¹·K⁻¹).

Now we put the known data in the equation, and solve for the value we're asked:

• (a) n = 1 mol; V = 12 L; P = 1 atm; T = ?

1 atm * 12 L = 1 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

T = 146.34 K

• (b) n = 1 mol; V = 25 L; P= 1 atm; T = ?

1 atm * 25 L = 1 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

T = 304.88 K

• (c) n = 1 mol; V = 25 L; T = 346 K; P = ?

P * 25 L = 1 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 346 K

P = 1.13 atm