Respuesta :

[tex]\bf \underset{\leftarrow \qquad \textit{\large 5x+8}\qquad \to }{\stackrel{6x-4}{\boxed{E}\rule[0.35em]{7em}{0.25pt}} F\stackrel{3x}{\rule[0.35em]{18em}{0.25pt}\boxed{G}}} \\\\\\ \stackrel{EG}{5x+8}~~=~~\stackrel{EF}{6x-4}~~+~~\stackrel{FG}{3x}\implies 5x+8=9x-4\implies 8=4x-4 \\\\\\ 12=4x\implies \cfrac{12}{4}=x\implies 3=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{EF}{6x-4}\implies 6(3)-4\implies 14[/tex]

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