Question

During a baseball game, a batter hits a high

pop-up.

If the ball remains in the air for 5.47 s, how

high does it rise? The acceleration of gravity

is 9.8 m/s.

Answer in units of m.

Answer 1

Answer:

53.60600 m

Explanation:

5.47 x 9.8

Answer 2

Answer:

The maximum height of the ball is 36.65 m.

Explanation:

Given that,

Time = 5.47 sec

The ball must be at top point in half of total time.

We need to calculate the height

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Where, s = height

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

$s=0+\dfrac{1}{2}\times9.8\times(\dfrac{5.47}{2})^2$

$s=36.65\ m$

Hence, The maximum height of the ball is 36.65 m.