Question

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Input in standard form the equation of the given line.
The line with m= -3/8 and passing through (5,-4)

Answer 1

Answer:

8x + 3y = -47

Step-by-step explanation:

    1. Use the y = mx + b form to find b:

$y=-\frac{3}{8} x+b\\-4=\frac{3}{8}(5)+b\\-32=15+8b\\-47=8b\\-\frac{47}{8} =b$

    2. Plug in b for the new equation:

$y=-\frac{3}{8} x-\frac{47}{8}$

    3. Get rid of the denominators and simplify everything into standard form

    (ax + by = c)

$y=-\frac{3}{8} x-\frac{47}{8}\\8y=-3x-47\\3x+8y=-47$

Answer 2

The standard forms the equation of the given line is $\rm y = -\dfrac{3}{8}x-\dfrac{17}{8}$.

Given that,

The line with m = -3/8 and passing through the point (5,-4)

We have to determine,

The standard forms the equation of the given line.

According to the question,

The standard form of the equation of the line is,

$\rm y = mx+c$

The line with m = -3/8 and passing through the point (5,-4).

Then,

$\rm y = mx+c\\\\-4 = \dfrac{-3}{8}\times 5 +c\\\\-4 = \dfrac{-15}{8} + c\\\\c = -4 + \dfrac{15}{8}\\\\c = \dfrac{-32+15}{8}\\\\c = \dfrac{-17}{8}$

Therefore,

The standard forms the equation of the given line is,

$\rm y = mx +c\\\\y= \dfrac{-3}{8} x+ \dfrac{-17}{8}\\\\y = -\dfrac{3}{8}x-\dfrac{17}{8}$

Hence, The standard forms the equation of the given line is $\rm y = -\dfrac{3}{8}x-\dfrac{17}{8}$.

For more details refer to the link given below,

https://brainly.com/question/13937209