Respuesta :
Answer:
368.3 g
Explanation:
Given data:
mass of chlorine= 0.568 Kg
sodium chloride= 936 g
mass of sodium= ?
To solve this problem first of all we will write the chemical equation:
Na + Cl2 → NaCl
Balanced chemical equation:
2Na + Cl2 → 2NaCl
Formula:
number of moles = mass/ molar mass
first of all we will calculate the moles of sodium chloride,
number of moles = 936 g/ 58.44 g/mol
number of moles = 16.061 mol
The number of moles of sodium required in this reaction is equal to the number of moles of NaCl produced, which can be seen in balance chemical equation.
Now we will compare the moles of sodium chloride and sodium
NaCl : Na
1 : 1
2 : 2
16.016 : 16.016
Now we will calculate the mass of sodium from moles
number of moles = mass / molar mass
number of moles × molar mass = mass
16.016 mol × 23 g/mol = mass
mass= 368.3 g
368.3 g is the mass of sodium.
When an element reacts with another to form a compound is called a combination reaction and here the sodium element reacts with the chloride to produce sodium chloride salt.
How to calculate the mass?
Given,
- Mass of chlorine [tex]\rm ({Cl})[/tex]= 0.568 Kg
- Mass of Sodium chloride [tex]\rm ({NaCl})[/tex] = 936 g
- Mass of sodium [tex]\rm ({Na})[/tex] = ?
The balanced chemical reaction can be shown as,
[tex]\rm 2Na + Cl_{2} \rightarrow \rm 2NaCl[/tex]
The moles of the sodium chloride will be given as,
[tex]\begin{aligned}\text{number of moles (n)} &= \dfrac{\rm mass}{\rm molar \;mass}\\\\\rm n &= \dfrac{936 \;\rm g}{58.44\;\rm g/mol}\\\\&= 16.061\;\rm mol\end{aligned}[/tex]
2 moles of sodium = 2 moles of sodium chloride
So,
16.016 moles of sodium = 16.061 moles of sodium chloride
Calculate the mass of the sodium as
[tex]\begin{aligned}\rm mass &= \text{Moles }\times \text{molar mass}\\\\&= 16.061 \;\rm g\times 23 \;\rm g/mol\\\\&= 368.3 \;\rm g\end{aligned}[/tex]
Therefore, 368.3 g is the mass of sodium.
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