Find f(x) and g(x) so that the function can be described as y = f(g(x)).

y = Four divided by x squared. + 9

f(x) = x + 9, g(x) = Four divided by x squared.
f(x) = x, g(x) = Four divided by x. + 9
f(x) = One divided by x., g(x) = Four divided by x. + 9
f(x) = Four divided by x squared., g(x) = 9

Respuesta :

Answer:

Listed below

Step-by-step explanation:

This is a function composition excercise. The idea is to sustitute the value of G(x) in the X's value of the other function.

a) [tex]f(x)=x+9[/tex] and [tex]g(x)=\frac{4}{x^{2} }[/tex]

So we replace g(x) on the X of the f(x) function and we get:

[tex]f(g(x))=\frac{4}{x^{2} } +9[/tex]

b) We do the same on this excercise:

[tex]f(x)=x[/tex] and [tex]g(x)[tex]f(g(x))=\frac{4}{x+9}[/tex][/tex]

We replace and we get:

c) And the same on this one:

[tex]f(x)=\frac{1}{x}[/tex] and [tex]g(x)=\frac{4}{x+9}[/tex]

We replace and we get:

[tex]f(g(x))=\frac{1}{\frac{4}{x+9} } = 1: \frac{4}{x+9} =1.\frac{x+9}{4} =\frac{x+9}{4}[/tex]

d) Exactly the same on this excercise:

[tex]f(x)=\frac{4}{x^{2} }[/tex] and [tex]g(x)=9[/tex]

We replace:

[tex]f(g(x))=\frac{4}{9^{2} } = \frac{4}{81}[/tex]

Answer:

im pretty sure its A

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