Question

what is the solutions to the quadratic equation (2b+3)^2=12

Answer 1

Answer:

Step-by-step explanation:do idk

Answer 2

The solution to the quadratic equation $(2 b+3)^{2}=12$  is $\bold{4 b^{2}+12 b-3=0}$

Solution:

Using the square of summation algebraic expansion formula for polynomials,

$(x+y)^{2}=x^{2}+y^{2}+2 x y$

Applying the formula on $(2 b+3)^{2}$

Here $x = 2b\ and\ y = 3$

Hence $(2 b+3)^{2}$ can be written as $(2 b)^{2}+(3)^{2}+(2 \times 2 b \times 3)=12$

On simplification,

$\begin{array}{c}{4 b^{2}+9+(2 \times 6 b)=12} \\ {4 b^{2}+9+12 b=12}\end{array}$

On moving 12 from right hand side to left hand side, it becomes negative (-12)

$4 b^{2}+9+12 b-12=0$

Rearranging the terms,  $4 b^{2}+12 b+9-12 = 0$

Subtract 9 from -12, we get   $4 b^{2}+12 b-3 = 0$