Respuesta :
Answer:
a)
i) at [1.0,2.0] = = -0.15 mg/ml¬hr
ii) at [1.5, 2.0] = - 0.12 mg/ml¬hr
iii) at [2.0, 2.5] = -0.12 mg/ml¬hr
(iv) at [2.0, 3.0] = -0.1 mg/ml¬hr
b) the instantaneous rate of change at t = 2 = 0.12 mg/ml¬hr and the unit will be h mg /ml
Explanation:
1) according to the table of the change in c (mg/ml) and the change in time (hours) So, we are going to use this formula to solve part (a)
m = ΔC / Δt
when m is the average change of c with respect to t over each time interval
i) [1.0,2.0] :
m = ΔC / Δt
= (0.16-0.31)/(2-1)
= -0.15 mg/ml¬hr
ii) [1.5, 2.0]:
m = ΔC / Δt
= (0.16-0.22)/(2-1.5)
= - 0.12 mg/ml¬hr
iii) [2.0, 2.5]:
m = ΔC / Δt
= (0.1 - 0.16)/(2.5-2)
= -0.12 mg/ml¬hr
(iv) [2.0, 3.0] :
m = ΔC / Δt
= (0.06-0.16)/(3-2)
= -0.1 mg/ml¬hr
(b) to estimate the instantaneous rate of change at t = 2 we can see the results at (ii) and (iii) at time rates [1.5, 2.0] and [2.0, 2.5] both are the same answer = -0.12 mg/ml¬hr so, the instantaneous rate of change at t=2 is equal -0.12 and the unit will be h mg/ml because (mg/ml) / h = mg h /ml
The study of chemicals and bonds is called chemistry.
The correct answer to the question is a)
i) at [1.0,2.0] = = -0.15 mg/ml¬hr
ii) at [1.5, 2.0] = - 0.12 mg/ml¬hr
iii) at [2.0, 2.5] = -0.12 mg/ml¬hr
(iv) at [2.0, 3.0] = -0.1 mg/ml¬hr
and
b) the instantaneous rate of change at t = 2 = 0.12 mg/ml¬hr and the unit will be h mg /ml
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- An alcoholic drink is a drink that contains ethanol, a type of alcohol produced by the fermentation of grains, fruits, or other sources of sugar that acts like a drug.
- The consumption of alcoholic drinks often referred to as "drinking", plays an important social role in many cultures.
1) according to the table of the change in c (mg/ml) and the change in time (hours), we are going to use this formula to solve part (a)
m = ΔC / Δt
when m is the average change of c with respect to t over each time interval
i) [1.0,2.0] :
m = ΔC / Δt
= (0.16-0.31)/(2-1)
= -0.15 mg/ml¬hr
ii) [1.5, 2.0]:
m = ΔC / Δt
= (0.16-0.22)/(2-1.5)
= - 0.12 mg/ml¬hr
iii) [2.0, 2.5]:
m = ΔC / Δt
= (0.1 - 0.16)/(2.5-2)
= -0.12 mg/ml¬hr
(iv) [2.0, 3.0] :
m = ΔC / Δt
= (0.06-0.16)/(3-2)
= -0.1 mg/ml¬hr
(b) to estimate the instantaneous rate of change at t = 2 we can see the results at (ii) and (iii) at time rates [1.5, 2.0] and [2.0, 2.5] both are the same answer = -0.12 mg/ml¬hr so, the instantaneous rate of change at t=2 is equal -0.12 and the unit will be h mg/ml because (mg/ml) / h = mg h /ml
Hence, the correct answer to the mentioned above.
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