Question

Graham is hiking at an altitude of 14,040 feet and is descending 50 feet each minute. Max is hiking at an altitude of 12,500 feet and is ascending 20 feet each minute . How many minutes will it take graham and max to meet at the same altitude

Answer 1

Answer:

The answer to your question is: 51.33 min

Step-by-step explanation:

Data

                         Graham                        Max

height              14040 ft                       12500 ft       difference  = 1540 ft

speed               50 ft/min                     20 ft/ min

Formula

                 v = d/t   clear d from this equation d = vt

Equation

                    Graham             Max

                       50t        =     1540 + 20t

Solve it          50t - 20t = 1540

                     30t = 1540

                     t = 1540 / 30

                     t = 51.33 min

Answer 2

Answer:

Graham and max will meet after 22 minutes, with  an altitude of 121,940 ft

Step-by-step explanation:

From the given example, we recall the following statements.

The altitude of Graham's hiking =14,040 feet

He is descending 50 feet each minute.

The altitude of Max hiking = 12,500

He is ascending 20 feet each minute .

Now,

let us find how many minutes will it take graham and max to meet at the same altitude

The starting distance = 14,040-12,500 = 1,540 ft

The distance between them decreases by (50+20) ft/min = 70 ft/min

So,

1540 ft *  (1 min)/(70 ft) = 22 min

Therefore, graham and max will meet after 22 minutes, and at an altitude of 121,940 ft