Answer:
[tex]a_1=4, \ a_n=4+a_{n-1},\ n>0[/tex]
Step-by-step explanation:
A group of students is arranging squares into layers to create a project.
You can see that each next layer has 4 more squares than previous one. Hence, for n>0
[tex]a_1=4, \\ \\a_2=8=4+a_1,\\ \\a_3=12=4+a_2,\\ \\...\\ \\a_n=4+a_{n-1}[/tex]
Answer:
D-a1 = 4; an = 4 + an − 1, n > 0
Step-by-step explanation:
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