Question

Please help me!!
f(x)= $\left[\begin{array}{ccc}x^2,&x\leq &1\\2x+1,&x\ \textgreater \ &1\end{array}\right]$

A.) Evaluate f(0)

Thanks fam

Answer 1

The piece wise function is written that if X is ≤1 use the top equation and if x is > 1 use the bottom equation.

f(0) means that X is = 0, so you would use the top equation:

x^2

Replace x with 0 to get 0^2 which is 0 x 0 = 0

F(0) = 0