Question

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If KM bisects JKL, m JKL = 92, and MKL = (5x+1), find the value of x.

Answer 1

Answer:

x = 9

Step-by-step explanation:

The trick here is knowing that JKM and MKL are equal, which means MKL is equal to JKL/2. From that knowledge, we can solve.

MKL = JKL/2

5x + 1 = 46

5x = 45

x = 9

Answer 2

Answer:

x=9

Step-by-step explanation:

Given information: KM bisects ∠JKL, m∠JKL = 92, and m∠MKL = (5x+1).

It is given that KM bisects ∠JKL. It means line KM divides the angle in two equal parts.

$m\angle JKM=m\angle MKL$                   .... (1)

The ∠JKL is the sum of ∠JKM and ∠MKL.

$m\angle JKM=m\angle JKM+m\angle MKL$

Using equation (1) we get

$m\angle JKM=m\angle MKL+m\angle MKL$             $m\angle JKM=m\angle MKL$

$m\angle JKM=2(m\angle MKL)$

Substitute m∠JKL = 92 and m∠MKL = (5x+1) in the above equation.

$92=2(5x+1)$

$92=2(5x)+2(1)$

$92=10x+2$

Subtract 2 from both sides.

$92-2=10x$

$90=10x$

Divide both sides by 10.

$\frac{90}{10}=x$

$9=x$

Therefore, the value of x is 9.