Answer:
Step-by-step explanation:
When two fair dice are tossed sample space consists of 36 events
(1,1)....(6,6)
A_ The difference of numbers is 2 or less
Favorable outcomes = [tex](1,1) (1,2) (1,3) (2,1) (2,2)(2,3) (2,4) (3,1) (3,2) (3,3) (3,4) (3,5) (4,2) (4,3)(4,5) (4,6) (5,3) (5,4) (5,6)\\[/tex]
Hence Probability = [tex]\frac{19}{36}[/tex]
B) A 4 does not appear on either die
Then we must not have these
[tex](4,1)(4,2)(4,3) (4,4) (4,5) (4,6)\\(1,4) (2,4) (3,4) (5,4) (6,4)[/tex]
Hence probability = [tex]\frac{36-11}{36} =\frac{25}{36}[/tex]
C: The sum of numbers is 10 or more:
FAvourable outcomes are:
[tex](4,6) (5,5) (5,6) (6,5) (6,4)[/tex]
Probability = [tex]\frac{5}{36}[/tex]