Answer:
16.98 g
Explanation:
The balacend equation is
Fe2O3(s) + 2Al(s) → 2Fe(l) + Al2O3(s)
So, when 2 moles of iron (Fe) are produced, 1 mol of aluminum oxide is produced. The mass molar of the elements are:
Fe = 56 g/mol; O = 16 g/mol; Al = 27 g/mol
Then, the mass molar of Al2O3 is:
2x27 + 3x16 = 102 g/mol
The stoichiometry relation will be:
2 mol of Fe -------------------- 1 mol of Al2O3
2x56 g of Fe -------------------- 102 g of Al2O3
18.65 g of Fe -------------------- x g of Al2O3
By a direct simple three rule:
112x = 1902.3
x = 16.98 g