Question

Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the equation using the​ slope-intercept form.

Answer 1

Answer:

The answer to your question is:

    y = -2/3 x + 6   or 2x + 3y -18 = 0

Step-by-step explanation:

Point (-9, 12)

Perpendicular to y = 3/2 x -1/2

then    slope = m = 3/2   but we change it,  so  m = -2/3

               y -12 = -2/3 (x + 9)

              3(y -12) = -2( x + 9)

               3y - 36 = -2x - 18

  General equation      2x + 3y -36 + 18 = 0

                                      2x + 3y - 18 = 0

slope y-intercept           3y = -2x -18 +36

                                       3y = -2x + 18

                                        y = -2/3 x + 18/3

                                        y = -2/3x + 6