Answer: 1.02 s
Explanation:
In this situation the following equation will be useful:
[tex]V=V_{o}+at[/tex]
Where:
[tex]V=25.8 m/s[/tex] is Marissa's car final velocity
[tex]V_{o}=24.5 m/s[/tex] is Marissa's car initial velocity
[tex]a=1.269 m/s^{2}[/tex] is Marissa's car constant acceleration (assuming this is the acceleration, since 1269 m/s^{2} does not make sense)
[tex]t[/tex] is the time it takes to accelerato from [tex]V_{o}[/tex] to [tex]V[/tex]
Isolating [tex]t[/tex]:
[tex]t=\frac{V-V_{o}}{a}[/tex]
[tex]t=\frac{25.8 m/s-24.5 m/s}{1.269 m/s^{2}}[/tex]
[tex]t=1.02 s[/tex]