Question

A quarterback takes the ball from the line of scrimmage, runs backwards for 9.0 yards, then runs sideways parallel to the line of scrimmage for 15.0 yards. At this point, he throws a 54.0-yard forward pass straight down field, perpendicular to the line of scrimmage. What is the magnitude of the football's resultant displacement?

Answer 1

Answer:

$d = 47.43 yards$

Explanation:

Displacement of the quarterback in backward direction is

$x = - 9 Yards$

Now the displacement parallel to the line of scrimmage

$y = 15 yards$

now the displacement in forward direction is given as

$x_2 = 54 yards$

now total displacement in x direction is

$x = 54 - 9$

$x = 45 yards$

$y = 15 yards$

net displacement is given as

$d = \sqrt{x^2 + y^2}$

$d = \sqrt{45^2 + 15^2}$

$d = 47.43 yards$