Respuesta :

3. First solve the differential equation:

[tex]\dfrac{\mathrm dT}{\mathrm dt}=-k(T-A)[/tex]

This is separable, as

[tex]\dfrac{\mathrm dT}{T-A}=-k\,\mathrm dt[/tex]

Integrating both sides gives

[tex]\ln|T-A|=-kt+C[/tex]

[tex]\implies T-A=e^{-kt+C}=Ce^{-kt}[/tex]

[tex]\implies T(t)=A+Ce^{-kt}[/tex]

Now use the given known temperatures at the specified times to solve for the unknown constants. The egg starts with a temperature of [tex]T(0)=100[/tex]; it cools to 90º C after 1 minute so that [tex]T(1)=90[/tex]; and the ambient temperature is [tex]A=30[/tex].

[tex]T(0)=100\implies100=30+C\implies C=70[/tex]

[tex]T(1)=90\implies90=30+70e^{-k}\implies\dfrac67=e^{-k}\implies-k=\ln\dfrac67[/tex]

So the temperature of the egg at time [tex]t[/tex] is

[tex]T(t)=30+70e^{t\ln\frac67}[/tex]

and after 4 minutes it will have cooled to about

[tex]T(4)=30+70e^{4\ln\frac67}\approx68[/tex]

but unfortunately none of the provided answers are correct...

4. Vertical tangents occur wherever [tex]\frac{\mathrm dy}{\mathrm dx}[/tex] is undefined, and horizontal tangents occur wherever the derivative is 0. This means the slope field will show vertical tangents when [tex]y=3[/tex], so (I) is true, but (II) is not.

(III) is also true because, for instance, we can pick infinitely many values of [tex]y[/tex] so long as [tex]x=-1[/tex], for which we get horizontal tangent lines.

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