Question

When a person sings, his or her vocal cords vibrate in a repetitive pattern having the same frequency of the note that is sung. If someone sings the note B flat that has a frequency of 466 Hz , how much time does it take the person's vocal cords to vibrate through one complete cycle, and what is the angular frequency of the cords?

Answer 1

Explanation:

Given that,

Frequency of the note B flat, f = 466 hz

Let t is the time taken by the person's vocal cords to vibrate through one complete cycle. It can be calculated as :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{466\ Hz}$

T = 0.00214 seconds

$T=2.14\times 10^{-3}\ s$

Let $\omega$ is the angular frequency of the cords. The angular frequency is given by :

$\omega=2\pi f$

$\omega=2\pi \times 466$

$\omega=2927.96\ rad/s$

$\omega=2.927\times 10^3\ rad/s$

Hence, this is the required solution.