Explanation:
Given that,
Angular frequency 1, [tex]\omega_1=2.7\times 10^{15}\ rad/s[/tex]
Angular frequency 2, [tex]\omega_2=4.7\times 10^{15}\ rad/s[/tex]
When light having vibrations with angular frequency ranging from [tex]\omega_1[/tex] to [tex]\omega_2[/tex] strikes the retina of the eye, it stimulates the receptor cells there and is perceived as visible light. We need to find the limits of the period of this light.
We know that,
[tex]\omega=2\pi f[/tex]
[tex]f=\dfrac{\omega}{2\pi}[/tex]
Time period, [tex]T=\dfrac{1}{f}=\dfrac{2\pi}{\omega}[/tex]
[tex]T_1=\dfrac{2\pi}{2.7\times 10^{15}}[/tex]
[tex]T_1=2.32\times 10^{-15}\ s[/tex]
[tex]T_2=\dfrac{2\pi}{4.7\times 10^{15}}[/tex]
[tex]T_2=1.33\times 10^{-15}\ s[/tex]
So, the limits of the period of this light is from [tex]2.32\times 10^{-15}\ s[/tex] to [tex]1.33\times 10^{-15}\ s[/tex]. Hence, this is the required solution.