Answer:
No
Explanation:
If the mother has a phenotype AB, she only can have the genotype [tex]I^{A}I^{B}[/tex]. This because A and B are codominant alleles. The child is blood type A, so he can be heterozygote or homozygote for allele B. The possible father is blood type A and he can be heterozygote or homozygote for allele A. Hence, possibles genotypes are:
Mother: [tex]I^{A}I^{B}[/tex]
Child: [tex]I^{B}I^{B}[/tex] or [tex]I^{B}I^{o}[/tex]
Possible father: [tex]I^{A}I^{A}[/tex] or [tex]I^{A}I^{o}[/tex]
If the father is [tex]I^{A}I^{A}[/tex], children of these parents can have the genotypes shown in the first Punnet Square.
And, if the father is [tex]I^{A}I^{o}[/tex], possible progeny will be the one on the second Punnet Square.
So, it is impossible for this couple to have a son blood type A.