Question

does anyone understand how to do this? im stuck

Answer 1

dy/dx = y/x^2
1/y dy = 1/x^2 dx
int(1/y dy) = int(1/x^2 dx)
ln y + c1 = -x + c2
ln y = -x + c ; c= c2-c1
y = e^(-x+c) = e^c e^-x
y = Ce^-x ; C=e^c