Question

identify the features of the graph

Answer 1

There is a parabola that opens upwards with a line of symmetry at x=3 and the vertex is at (3, -4).

Answer 2

Answer:

Step-by-step explanation:

On seeing the graph we find that x intercepts are 1 and 5.

Also y intercept is 5

Vertex is at (3,-4) and also parabola is open up.

The possible equations can be of the form

y =a(x-1)(x-5)

y =a(x^2-6x+5)

When x=0, y =6

Hence 6 =5a

a =6/5

Solution is

$y=\frac{6}{5} (x-1)(x-5)$