Question

A space vehicle deploys its re–entry parachute when it's traveling at a vertical velocity of –150 meters/second (negative because the parachute is going down.) It comes to rest at 0 meters/second after 30 seconds. What's the average acceleration of the shuttle during this time span?

A. -0.2 meters/second2
B. -5 meters/second2
C. 0.2 meters/second2
D. 5 meters/second2

Answer 1

Answer: OPTION D.

Explanation:

We can use the Kinematic formula for an object under constant acceleration:

$V_f=V_0+at$

Where $V_F$ is the final velocity, $V_0$ is the initial velocity, "a" is the acceleration and "t" is the time.

In this case we know that:

$V_f=0\ \frac{m}{s}\\\\V_0=-150\ \frac{m}{s}\\\\t=30\ s$

Therefore, we must substitute these values into the formula and solve for "a":

$0\ \frac{m}{s}=-150\ \frac{m}{s}+a(30\ s)\\\\a=\frac{150\ \frac{m}{s}}{30\ s}\\\\a=5\ \frac{m}{s^2}$

Answer 2

Answer:

D. 5 meters/second2

Explanation:

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