Question

The combustion of titanium with oxygen produces titanium dioxide: Ti(s) + O2(g) → TiO2(s) When 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °C to 91.60 °C. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. The heat of reaction for the combustion of a mole of Ti in this calorimeter is __________ kJ/mol.

Answer 1

The heat of reaction for the combustion of a mole of Ti in this calorimeter is - 1.52 × 10^4 KJ/mol.

The equation of the reaction is;

Ti(s) + O2(g) → TiO2(s)

From the available information;

Temperature difference(θ) =  91.60 °C -  25.00 °C = 66.6°C

heat capacity of calorimeter (Cp) = 9.84 kJ/K

Heat absorbed by the calorimeter = cpθ = 9.84 × 10^3 J/K × 66.6°C

= 655.3 KJ

Number of moles of Ti = 2.0600 / 47.867 = 0.0430 mol

Enthalpy of combustion in KJ/mol = -(655.3 KJ)/0.0430 mol

= - 1.52 × 10^4 KJ/mol

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