Answer:
[tex]\dfrac{1}{9}[/tex]
Step-by-step explanation:
4 people use all three facilities, then
At least two facilities use 4 + 12 + 5 + 15 = 36 people, 4 of them use all three facilities. Thus, the probability that a randomly selected person which uses at least two facilities, uses all the facilities is
[tex]\dfrac{4}{36}=\dfrac{1}{9}[/tex]