Question

An object having a net charge of 25.0 µC is placed in a uniform electric field of 620 N/C directed vertically. What is the mass of this object if it "floats" in the field?

Answer 1

Answer:

Mass of the object, $m=1.58\times 10^{-3}\ kg$

Explanation:

It is given that,

Charge on an object, $q=25\ \mu C=25\times 10^{-6}\ C$

Electric field, E = 620 N/C

We need to find the mass of this object. Let m is the mass of the object. It can be calculated as :

$ma=qE$

$m=\dfrac{qE}{a}$, here a = g (as it is vertically downward)

$m=\dfrac{25\times 10^{-6}\times 620}{9.8}$

m = 0.00158 kg

$m=1.58\times 10^{-3}\ kg$

So, the mass of the object is $1.58\times 10^{-3}\ kg$. Hence, this is the required solution.