A manometer measures a pressure difference as 65 inches of water. Take the density of water to be 62.4 lbm/ft3.What is this pressure difference in pound-force per square inch, psi?

Respuesta :

Answer:

P = 75.1 PSI

Explanation:

Conceptual analysis

P = ρ×g×h Formula (1)

ρ: fluid density in lbm/ft³

g: acceleration due to gravity in ft/s²

h: fluid height in ft

Known information

We have the following data:

ρ = 62.4 lbm/ft³

g = 32 ft/s²

h = 65 inches of water = 65/12 ft of water

[tex]1 poundal = 1 \frac{lbm*ft}{s^2}[/tex]

1 ft = 12 in

Problem development

We replace in formula (1):

[tex]P = 62.4 \frac{lbm}{ft} * 32 \frac{ft}{s^2} * \frac{65}{12}  ft = 10816 \frac{poundal}{ft^2}[/tex]

[tex]P = 10816 poundal*\frac{1}{ft^2} = 10816 poundal * \frac{1}{144in^2} = 75.1 \frac{poundal}{in^2} = 75.1 PSI[/tex]