Answer:
2.866 x 10^8 J
Explanation:
Thermal conductivity, K = 0.040 W/m^2 k
Area of the wall, A = 470 m^2
Thickness, d = 17 cm = 0.17 m
difference in temperature, ΔT = 30° C
The rate of heat flow is H.
Time, t = 1 day = 1 x 24 x 60 x 60 second = 86400 second
By use of formula of heat flow
[tex]H=\frac{K A \Delta T}{d}t[/tex]
[tex]H=\frac{0.040 \times 470 \times 30}{0.17}\times 86400[/tex]
H = 2.866 x 10^8 J